七．银行家算法程序代码 #include #include #include using namespace std; typedef struct Max1 // 资源的最大需求量 { int m_a; int m_b; int m_c; }Max; typedef struct Allocation1 //已分配的资源数 { int a_a; int a_b ; int a_c; }Allocation; typedef struct Need1 //还需要的资源数 { int n_a;
acm第100题 The 3n+1 problem #include using namespace std; unsigned CyCle(unsigned m) { unsigned count = 1; while (m != 1) { if (m & 0x01) m = 3 * m + 1; else m = m / 2; count++; } return count; } int main() { unsigned i,j; while (scanf("%u %u",&i,&j)
# include # include #include # define n 3 int main () { int i,j,k,row,v,t; int M[n]; float m,r,max0,max1; float a[n][n],b[n],s[n],l[n][n],u[n][n],x[n],y[n]; a[0][0]=0.5,a[0][1]=1.1,a[0][2]=3.1; a[1][0]=5.0,a[1][1]=0.96,a[1][2]=6.5; a[2][0]=2.0,a[2][
function [c,err,yc]=bisect(f,a,b,delta) ya=feval(f,a); yb=feval(f,b); if ya*yb>0,break,end max1=-1+round((log(b-a)-log(delta))/log(2)); for k=1:max1 c=(a+b)/2; yc=feval(f,c); if yc==0 a=c; b=c; elseif yb*yc>0 b=c; yb=yc; else a=c; ya=yc; end i
