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文件名称: 有限状态机的c语言实现
  所属分类: C/C++
  开发工具:
  文件大小: 2kb
  下载次数: 0
  上传时间: 2015-10-26
  提 供 者: qing****
 详细说明: #include int main() { int state_key = 1; //钥匙状态 为1时钥匙区有钥匙,为时钥匙区 无钥匙 int state_hold = 0; // 钥匙持有状态 为1时持有钥匙,为时 未持有钥匙 int state_door = 0; //门状态 0:关闭 1:打开 int state_lock = 1; //上锁状态 1:上锁 0:解锁 int order; // 用于存放用户输入指令 printf("this is a game.\n"); printf ("if you want to OPEN THE DOOR ,input 1\n"); printf ("if you want to CLOSE THE DOOR ,input 2\n"); printf ("if you want to LO CK THE DOOR ,input 3\n"); printf ("if you want to UNLOCK THE DOOR,input 4\n"); // printf ("if you want to LOCK THE DOOR ,input 5\n"); printf("please input the order\n"); while(1) { scanf("%d",&order); // if(order!=(1||2||3||4)) // { // printf("worng input ,please input again.\n"); // continue; // } switch(order) { case 1 : if(state_door==1) { printf("the door has been opened before\n"); break; } if(state_lock==1) { printf("the door has been lock\n"); break; } state_door=1; break; case 2: if(state_door==0) { printf("the door has been closed before\n"); break; } if(state_lock==1) { printf("the door has been lock\n"); break; } state_door=0; break; case 3: if(state_door==1) { printf("the door has been opened before\n"); break; } if(state_lock==1) { printf("the door has been lock\n"); break; } state_lock=1; break ; case 4: if(state_door==1) { printf("the door has been opened before\n"); break; } if(state_lock==0) { printf("the door has not been lock\n"); break; } state_lock=0; break ; } } } ...展开收缩
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